g = {
1:[2,3],
2:[4,5],
3:[6,7],
4:[],
5:[8],
6:[],
7:[],
8:[]
}
v = []
def dfs(g,v,n):
print(n,end=' ')
v.append(n)
for nb in g[n]:
if nb not in v:
dfs(g,v,nb)
dfs(g,v,1)
print()
v=[]
q = []
def bfs(g,v,n):
q.append(n)
while q:
p=q.pop(0)
if p not in v:
print(p,end=' ')
v.append(p)
for nb in g[p]:
if nb not in v:
q.append(nb)
bfs(g,v,1)
# 執行結果
# 1 2 4 5 8 3 6 7
# 1 2 3 4 5 6 7 8
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